Heat Energy

To determine the amount of heat energy possessed by a body, three key factors are considered:

The quantity of heat (Q) is given by the equation:

$$ Q = mcΔθ $$

Heat energy is measured in Joules (J).

Heat Capacity

Heat capacity is the amount of heat required to raise the temperature of a substance by one degree. It is measured in Joules per Kelvin (J/K).

Mathematically, it is expressed as:

Heat capacity = Mass × Specific heat capacity

$$ C = mc $$

Specific Heat Capacity

The specific heat capacity of a substance is the heat required to raise the temperature of one unit mass of the substance by one degree.

The amount of heat energy received by a body depends on:

The formula for heat energy is:

$$ Q = mcΔθ $$

Or, in expanded form:

$$ Q = mc(θ_2 - θ_1) $$

Determining Specific Heat Capacity

The specific heat capacity (C) is a proportionality constant that depends on the nature of the substance. It is given by:

$$ C = \frac{Q}{m(θ_2 - θ_1)} $$

The unit of specific heat capacity is J/gK.

Methods for Determining Specific Heat Capacity

Determination of Specific Heat Capacity by the Mixture Method

To determine the specific heat capacity of a solid lead block using the mixture method, follow these steps:

Heat Energy Balance

Using the principle of heat exchange:

Heat lost by the lead = Heat gained by the calorimeter and water

Given:

The heat balance equation is:

\[ M_s C_s (\theta_2 - \theta_3) = M_c C_c (\theta_3 - \theta_1) + (M_{cw} - M_c) C_w (\theta_3 - \theta_1) \]

Rearranging to solve for \( C_s \):

\[ C_s = \frac{M_c C_c (\theta_3 - \theta_1) + (M_{cw} - M_c) C_w (\theta_3 - \theta_1)}{M_s (\theta_2 - \theta_3)} \]

This equation allows the calculation of the specific heat capacity of lead based on experimental data.

Determining the Specific Heat Capacity of a Solid

To calculate the specific heat capacity (Cb) of a solid brass block, the following setup is used:

Assuming no heat is lost to the surroundings, the total electrical heat energy supplied by the heating coil is equal to the heat energy absorbed by the brass block.

Heat energy supplied by the coil = Heat energy gained by the brass

\( IVt = M C_b \Delta \theta \)

Where:

Applying Ohm's Law

From Ohm’s law:

\( V = IR \)

Substituting into the heat equation:

\( I^2 R t = M C_b \Delta \theta \)

Rearranging:

\( I^2 t R = M C_b \Delta \theta \)

Determining the Specific Heat Capacity of a Liquid

For a liquid, the total heat energy supplied by the coil is equal to the sum of the heat energy gained by the liquid and the heat energy gained by the calorimeter.

Heat energy supplied by the coil = Heat energy gained by the liquid + Heat energy gained by the calorimeter

\( IVt = M_l C_l \Delta \theta + M_c C_c \Delta \theta \)

Where: